목록2024/08/23 (1)
on my way

def solution(babbling): words = [ "aya", "ye", "woo", "ma"] for i, b in enumerate(babbling): for w in words: if w in b: babbling[i] = babbling[i].replace(w," ") return len([True for b in babbling if not b.strip()])
algorithm/Python
2024. 8. 23. 22:38